SOAL LATIHAN/TUGAS KALKULUS - PERTEMUAN 15
Nama : Tubagus Ardian Maulana
Kelas : 01TPLP015
NIM : 201011400661
dit = ƒ ‘(0) dan ƒ ‘(NIM)
jawab :
ƒ(x) = -x - x2 + 5
Turunan ƒ ‘(x) = -1 2 . - x2-1
= -1 - 2x
Substitusi ƒ ‘(0) = -1 -2(0)
= -1 - (0)
= -1
ƒ ‘(NIM) = ƒ ‘(1) = -1 - 2x
= -1 - 2(1)
= -1 – 2
= -3
dit = ɡ ‘(1) dan g ‘’(1)
jawab :
ɡ (x) = (x-1)2 + 5
= (x-1) (x-1) + 5
= x2 – x – x + 1 + 5
= x2 - 2x + 1 + 5
= x2 - 2x + 6
Turunan ɡ ‘(x) = 2 . x2-1 - 2 + 0
= 2x - 2
Substitusi
ɡ ‘(1) = 2x - 2 ɡ ‘’(x) = 2x - 2
= 2(1) - 2 ɡ ‘’(1) = 2
= 0
3. g (t) = 1 / t² ;
dit = t’ (0) , t ‘(1) , t’’(1)
Jawab : g (t) = 1 / t² = t ˉ²
g’ (t) = - 2 t ˉᶟ
t’ (0) = -2 x 0 ᶟ = 0
t’ (1) = -2 x 1ᶟ = -2
t’’ (1) = 6 x 1 ⁴ = 6
4. y = NIM x - sin x cari y ‘dit = y ‘
jawab :
y = 1x – sin x
y = 1 - cos x
r’(s) = 1 / 2 √1s + 1
r’’ (s) = - 1 / √1s + 1 (1s + 1)
Jawab :
a) r’ (0) = 1 / 2 √ 1 x 0 + 1 = 1 / 2
b) r’ (1) = 1 / 2 √ 1 x 1 + 1 = √2 /2
c) r’’ (2) = - 1 / √1 x 2 + 1 (1 x 2 + 1) = - √3 / 121
5
Komentar
Posting Komentar