SOAL LATIHAN/TUGAS KALKULUS - PERTEMUAN 15

Nama    : Tubagus Ardian Maulana
Kelas     : 01TPLP015
NIM      : 201011400661

1. ƒ(x) = -x - x2 + 5

dit = ƒ ‘(0) dan ƒ ‘(NIM)

jawab :

ƒ(x) = -x - x2 + 5

Turunan  ƒ ‘(x) = -1 2 . - x2-1

= -1 - 2x               

Substitusi  ƒ ‘(0) = -1 -2(0)

                                = -1 - (0)

                                = -1

                 ƒ ‘(NIM) = ƒ ‘(1) = -1 - 2x

                                                = -1 - 2(1)

                                                = -1 – 2

                                                = -3

2. ɡ (x) = (x-1)2 + 5

dit = ɡ ‘(1) dan g ‘’(1)

jawab :

ɡ (x) = (x-1)2 + 5

         = (x-1) (x-1) + 5

         = x2 – x – x + 1 + 5

         = x2 - 2x + 1 + 5

         = x2 - 2x + 6

                Turunan  ɡ ‘(x) = 2 . x2-1 - 2  + 0

                                                = 2x - 2

                Substitusi

                ɡ ‘(1) = 2x - 2                      ɡ ‘’(x) = 2x - 2                    

                           = 2(1) - 2                  ɡ ‘’(1) = 2

                           = 0

3. g (t) = 1 / t² ;       

dit = t’ (0) , t ‘(1) , t’’(1)

Jawab : g (t) = 1 / t² = t ˉ²

               g’ (t) = - 2 t ˉᶟ

 t’ (0) = -2 x 0 ᶟ = 0

 t’ (1) = -2 x 1ᶟ = -2

 t’’ (1) = 6 x 1 ⁴ = 6


4. y = NIM x - sin x cari y ‘dit = y ‘

jawab :

y = 1x – sin x

y = 1 - cos x

 

5. r (s) = √1s + 1 ; r’(0) , r’ (1) , r’’ (2)

r’(s) = 1 / 2 √1s + 1

r’’ (s) = - 1 / √1s + 1 (1s + 1)

Jawab :

a) r’ (0) = 1 / 2 √ 1 x 0 + 1 = 1 / 2

b) r’ (1) = 1 / 2 √ 1 x 1 + 1 = √2 /2

c) r’’ (2) = - 1 / √1 x 2 + 1 (1 x 2 + 1) = - √3 / 121

5

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